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Home/ Questions/Q 8768705
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T17:08:06+00:00 2026-06-13T17:08:06+00:00

I just want to know if there is any difference (especially in terms of

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I just want to know if there is any difference (especially in terms of performance) between these two approaches:

1)

$('.container').append('<div class="divChild">test div</div>'); 
$('.container .divChild').click(function() { alert('test'); });

2)

var $childDiv = $('<div class="divChild">test div</div>');
$childDiv.appendTo($('.container')).click(function() { alert('test'); });

So basically the second approach seems to be much faster since I don’t really have to search for the divChild div twice, but I need to add click event to the div.
Is that so?

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  1. Editorial Team
    Editorial Team
    2026-06-13T17:08:07+00:00Added an answer on June 13, 2026 at 5:08 pm

    The first point to make here is: Unless you’re doing this a lot (thousands of times in a very short period of time), it’s unlikely to matter.

    But I would suspect the most efficient thing to do would be to remember the result of $('.container') and then use children on it:

    var c = $('.container');
    c.append('<div class="divChild">test div</div>'); 
    c.children('.divChild').click(function() { alert('test'); });
    

    Or actually, technically, you don’t need the variable:

    $('.container')
        .append('<div class="divChild">test div</div>')
        .children('.divChild')
          .click(function() { alert('test'); });
    

    But I find long chains like that hard to read, hard to maintain, and hard to debug.

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