Question

I just wanted to know–is this the correct way to pass a pointer to a 2-D Array by reference in a function?

bool test::testTheNumber(test (*arr)[9][9], int testNumber, int row, int column)
{
    if(theRow(arr, testNumber, row) && theColumn(arr, testNumber, column))
     ....
}

My “theRow” and “theColumn” answers are very similar to the test function:

bool sodoku::theRow(sodoku (*arr)[9][9], int testNumber, int row)

bool sodoku::theColumn(sodoku (*arr)[9][9], int testNumber, int column)

In my main.cpp, I have a pointer to a 2d array and I called my functions like this:

test *arr[9][9];
theRow(arr,0,0);
theColumn(arr,0,0);
testTheNumber(arr,0,0,0,0);

Would the array pass by reference or would I have to use a & instead of a *? I am just a little confused as I’m not entirely sure how 2-D arrays would work.

Thanks.

Answer 1

This

bool test::testTheNumber(test (*arr)[9], int testNumber, int row, int column)
{
    if(theRow(arr, testNumber, row) && theColumn(arr, testNumber, column))
     ....
}

Or

bool test::testTheNumber(test arr[][9], int testNumber, int row, int column)
{
    if(theRow(arr, testNumber, row) && theColumn(arr, testNumber, column))
     ....
}

The first dimension in the array isn’t needed.

Really, arrays are passed by reference by default. You don’t need a &.

For more information, you may want to read this answer to this question.