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Home/ Questions/Q 6574493
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:16:06+00:00 2026-05-25T15:16:06+00:00

I just wrote a tiny method to count the number of pages for cell

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I just wrote a tiny method to count the number of pages for cell phone SMS. I didn’t have the option to round up using Math.ceil, and honestly it seems to be very ugly.

Here is my code:

public class Main {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
   String message = "today we stumbled upon a huge performance leak while optimizing a raycasting algorithm. Much to our surprise, the Math.floor() method took almost half of the calculation time: 3 floor operations took the same amount of time as one trilinear interpolation. Since we could not belive that the floor-method could produce such a enourmous overhead, we wrote a small test program that reproduce";

   System.out.printf("COunt is %d ",(int)messagePageCount(message));



}

public static double messagePageCount(String message){
    if(message.trim().isEmpty() || message.trim().length() == 0){
        return 0;
    } else{
        if(message.length() <= 160){
            return 1;
        } else {
            return Math.ceil((double)message.length()/153);
        }
    }
}

I don’t really like this piece of code and I’m looking for a more elegant way of doing this. With this, I’m expecting 3 and not 3.0000000. Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:16:07+00:00Added an answer on May 25, 2026 at 3:16 pm

    To round up an integer division you can use

    import static java.lang.Math.abs;
    
    public static long roundUp(long num, long divisor) {
        int sign = (num > 0 ? 1 : -1) * (divisor > 0 ? 1 : -1);
        return sign * (abs(num) + abs(divisor) - 1) / abs(divisor);
    }
    

    or if both numbers are positive

    public static long roundUp(long num, long divisor) {
        return (num + divisor - 1) / divisor;
    }
    
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