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Home/ Questions/Q 8736921
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T10:24:19+00:00 2026-06-13T10:24:19+00:00

I keep getting a syntax error on the while loop, and I’m not understanding

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I keep getting a syntax error on the while loop, and I’m not understanding why.

def main():
    n=1
    i=1
    flag=True
    num1=eval(input("Enter number")
    while i<9:
        n=n+1
        num2=eval(input("Enter number", n))
        r=r+1
        if num2<num1:
            flag=False
        num1=num2
    if flag==True:
        print("yes")
    else:
        print("no")
main()
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  1. Editorial Team
    Editorial Team
    2026-06-13T10:24:20+00:00Added an answer on June 13, 2026 at 10:24 am
    def main():
    n=1
    i=1
    flag=True
    num1=eval(input("Enter number"))
    while i<9:
        n=n+1
        num2=eval(input("Enter number", n))
        i+=1
        if num2<num1:
            flag=False
        num1=num2
    if flag==True:
        print("yes")
    else:
        print("no")
    main()
    

    You left a parameter open at num1=eval(input(“Enter number”))

    I also changed r = r + 1 to r+=1, they do the same thing but it reads a little bit nicer.

    you can also insure that the number is an integer by changing it to:

    num1=int(input(“Enter number: “))

    Also, I think the n+=1 needs to be i+=1 to end the infinite loop.

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