Question

I keep getting this error…but yet I cannot see any syntax that is inappropriate… any ideas?
Here’s my PHP code. I know my other pages are correct as I can run all other parts of the code with no issue.

<?php 

// this connects To database
$hostname="";    
$username="";   
$password="";    
$dbname="";     

mysql_connect($hostname,$username,$password) OR DIE ("Connection Failed");
mysql_select_db($dbname);


$action = $_REQUEST["action"];
if ($action == 'a') {
$custFirst = null;
$custLast = null;
$custAddress = null;
$custCity = null;   
$custState = null;
$custZip = null;
$custEmail = null;
$custPhone = null;
 } else {
$id = $_REQUEST["id"];
    $query = "select * from custTab where custNo = $id";
    $result = mysql_query($query) 
        or die(mysql_error());
    $row = mysql_fetch_array($result);
    $custFirst = $row['custFirst'];  
    $custLast = $row['custLast'];  
    $custAddress = $row['custAddress'];  
    $custCity = $row['custCity'];
    $custState = $row['custState'];
    $custZip = $row['custZip'];
    $custEmail = $row['custEmail'];
    $custPhone = $row['custPhone'];
} // end if

?>

Answer 1

Try putting quotes around the $id,

$query = "select * from custTab where custNo = '$id'";