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Home/ Questions/Q 6889733
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T06:11:36+00:00 2026-05-27T06:11:36+00:00

I keep getting zero as my time. I need to calculate the total time

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I keep getting zero as my time. I need to calculate the total time and the average time for searching though the hash table. Can someone please tell me what i am doing wrong?

void HashTable_chaining::SearchChainingHT(vector<string> QueryArray)
{
    clock_t start, stop, time = 0;
    int i = 0;
    while(i != QueryArray.size())
    {
        start = clock();
        find(QueryArray[i]);
        stop = clock();
        time += stop - start;
        i++;
    }
    time = (double)(time/CLOCKS_PER_SEC)*1000;
    cout << "\nThe total time for Search Chaining was " << time << "\nThe average time was " << time/QueryArray.size();
}
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  1. Editorial Team
    Editorial Team
    2026-05-27T06:11:37+00:00Added an answer on May 27, 2026 at 6:11 am

    You’re doing integer division:

    (double)(time/CLOCKS_PER_SEC)*1000;
    

    you want the cast inside the () instead:

    ((double)time/CLOCKS_PER_SEC)*1000;
    

    Furthermore, I’m not sure why you are assigning it back to time since that’s an integer variable. If you wanted it in milliseconds, you might want to make it explicit:

    cout << "\nThe total time for Search Chaining was " << time << "  (milliseconds)" << ...
    

    EDIT :

    I overlooked this initially (because of the horizontal scrolling), but you also have integer division here at the end of the printing line:

    .. << "\nThe average time was " << time/QueryArray.size();
    

    You may want to cast that one to double as well.

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