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Home/ Questions/Q 6326555
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:06:50+00:00 2026-05-24T17:06:50+00:00

I keep seeing codes like this: $(document.documentElement).keyup( function(event) { var slides = $(‘#slides .pagination

  • 0

I keep seeing codes like this:

  $(document.documentElement).keyup( function(event) {
    var slides = $('#slides .pagination li'),
        current = slides.filter('.current');

    switch( event.keyCode ) {
      case 37: // Left arrow
        if ( slides.filter(':first').is( current ) ) {
          slides.filter(':last').find('a').click();
        } else {
          slides.eq( slides.index(current) - 1 ).find('a').click();
        }
        break;
      case 39: // Right arrow
        if ( slides.filter(':last').is( current ) ) {
          slides.filter(':first').find('a').click();
        } else {
          current.find('+ li').filter(':first').find('a').click();
        }
        break;
    }
  });

For a line like this: current = slides.filter('.current');, .filter() is a jquery method, right? Then shouldn’t it be current = $(slides).filter('.current');.

Does it work the way it is done in the code? Why?

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:06:50+00:00Added an answer on May 24, 2026 at 5:06 pm

    slides is a jQuery object so you don’t need to wrap it in $() like you do with a DOM object.

    So slides.filter('.current') works like $('#slides .pagination li').filter('.current'). It’s important to keep track of whether your objects are jQuery selectors, jQuery objects, and/or DOM objects.

    Some people like to name their jQuery objects like var $slides as a mental note.

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