Question

I know how to add a matrix below another matrix.

e.g A = [A; B];

I have two matrixes of different dimensions(both different number of columns and rows) and i need to add them up together. One matrix is the main one and the other one is being added to it. Both of them are in a for loop and so the dimension of the first matrix is keep changing.

e.g for i = 1 :3
      AngerHist = [AngerHist;Hist];
    end

When I run it is giving me this error :

??? Error using ==> vertcat CAT arguments dimensions are not consistent. – 

How do i do it? Any suggestions?

AngerHist = {}; DisgustHist = {};FearHist = {}; HappyHist = {}; SadHist = {};SurpriseHist = {};
Images = 'C:\Users\HP\Documents\MATLAB\Images';
List = dir(Images);
n= size(List,1);

for i = 3:n
    List1 = dir(fullfile(Images,List(i).name));
    m= size(List1,1);
    BASE_DIR = fullfile(Images,List(i).name);
    for j = 3: m
        I=List1(j).name;
        I1= imread(fullfile(BASE_DIR,I),'jpg');
        Name = List(i).name;
        switch (Name)
                 case 'Anger'
                     Hist = UniformLBP(I1);
                     AngerHist = {AngerHist;Hist};
                     break;
                 case 'Disgust'
                     Hist = UniformLBP(I1);
                     DisgustHist = {DisgustHist;Hist};
                     break;
                case 'Fear'
                    Hist = UniformLBP(I1);
                    FearHist = {FearHist;Hist};
                    break;
                case 'Happy'
                    Hist = UniformLBP(I1);
                    HappyHist = {HappyHist;Hist};
                    break;
                case 'Sad'
                    Hist = UniformLBP(I1);
                    SadHist = {SadHist;Hist};
                    break;
                case 'Surprise'
                    Hist = UniformLBP(I1);
                    SurpriseHist = {SurpriseHist;Hist};
                    break;
        end        

    end    
end

Answer 1

I think that you need to use cells:

A={};
A=[A;rand(2,3)];
A=[A;rand(3,4)];
A=[A;rand(4,5)];
A=[A;rand(6,5)];

The result is:

A = 
 [2x3 double]
 [3x4 double]
 [4x5 double]
 [6x5 double]