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Home/ Questions/Q 6968591
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T16:28:16+00:00 2026-05-27T16:28:16+00:00

I know how to do it with cout: cout << string << ‘c’ <<

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I know how to do it with cout:

cout << "string" << 'c' << 33;

But how to perform this so output is redirected to variable instead directly to standard out ?

const char* string << "string" << 'c' << 33; //doesn't work
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  1. Editorial Team
    Editorial Team
    2026-05-27T16:28:17+00:00Added an answer on May 27, 2026 at 4:28 pm

    Use std::stringstream from C++ standard library.

    It works like the following:

    std::stringstream ss;
    ss << "string" << 'c' << 33;
    std::string str = ss.str();
    const char* str_ansi_c = str.c_str();
    

    Keep in mind str still needs to be in the scope while you are using C-style str_ansi_c.

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