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Home/ Questions/Q 6839609
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:44:21+00:00 2026-05-26T23:44:21+00:00

I know I can do that: const arrayOfIntegers : Array[1..15] of Integer = (3,2,8,10,1,6,2,13,13,3,13,13,13,3,45);

  • 0

I know I can do that:

const
  arrayOfIntegers : Array[1..15] of Integer = (3,2,8,10,1,6,2,13,13,3,13,13,13,3,45);

But how can I do the following instead?

var
  arrayOfIntegers : Array[1..15] of Integer;
begin
  arrayOfIntegers := (3,2,8,10,1,6,2,13,13,3,13,13,13,3,45);
end;

As soon as I try to compile the code above I get E2029 ‘)’ expected but ‘,’ found

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:44:22+00:00Added an answer on May 26, 2026 at 11:44 pm

    A typical use will be the following:

    type
      TIntegerArray1to15 = Array[1..15] of Integer;
    const
      INIT_INT_1_15_ARRAY: TIntegerArray1to15 = (3,2,8,10,1,6,2,13,13,3,13,13,13,3,45);
    
    var
      arrayOfIntegers : TIntegerArray1to15;
    begin
      arrayOfIntegers := INIT_INT_1_15_ARRAY;
      .... use and update arrayOfIntegers[]
    end;
    

    You should better define your own type in this case (code won’t be slower or bigger, and you’ll be able to make assignments between instances of this type). And you’ll ensure that your array boundaries will be as expected (1..15).

    The const statement will be compiled as a “reference” array, which will be copied in your arrayOfIntegers local variable. I’ve made it uppercase, which a somewhat commmon usage when declaring constants (but not mandatory – this is just a personal taste).

    If you want your code to be more generic and reusable (which IMHO makes sense if you want to be a lazy programmer) you may rely on dynamic arrays, and/or array of const parameters (if your array start with index 0).

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