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Home/ Questions/Q 7045139
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:29:36+00:00 2026-05-28T02:29:36+00:00

I know I can do this by str.c_str() , but I do not want

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I know I can do this by str.c_str(),
but I do not want a character constant. I want a char so that I can make some modifications.

char* removeDup(char *s)
{


        int len = strlen(s);
        int p,q, idx = -1;
    for(p = 0; p< len; p++)
   {
    char temp = s[p];
    bool flag = true;
    for(q=0;q<p;q++)
    {
        if(s[q] == temp)
        {
            flag = false;
            break;
        }
    }
    if(flag == true)
    {
        s[++idx] = temp;
    }
}
    s[++idx] = '\0';
    return s;
}

if I call this function as below, I get errors;

string s = "abcde";
removeDuplicate(s.c_str());

I need to convert this s into char and not const char.

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:29:37+00:00Added an answer on May 28, 2026 at 2:29 am

    To get the underlying data from a std::string You can use:

    string::data() or string::c_str(), both return a const char *.

    In either case the returned data is const char * because the memory for it is allocated in some read only implementation defined region which an user program is not allowed to modify. Any attempt to modify the returned const char * would result in Undefined Behavior.

    So you cannot and should not(through const_cast) modify the returned character string.

    The only correct way to achieve this by creating a new char*, allocate it, and copy in the contents from the const char*:

    std::string myString = "blabla";
    char* myPtr = new char[myString.size() + 1];
    myString.copy(myPtr, myString.size());
    myPtr[myString.size()] = '\0';
    
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