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Home/ Questions/Q 7765235
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:07:04+00:00 2026-06-01T15:07:04+00:00

I know I can do this… RegExp.prototype.xtend = function(){ console.log(123) } y = new

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I know I can do this…

RegExp.prototype.xtend = function(){ console.log(123) }
y = new RegExp(/pattern/)
y.xtend()

I want to extend regex patterns in this format: /pattern/, so I can do…

/pattern/.xtend()

Edit: It was a problem with syntax

Turns out it was a missing semi-colon. I need a semi-colon before the regex pattern otherwise it gives syntax error.

Thanks for all the comments. Works great now.

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  1. Editorial Team
    Editorial Team
    2026-06-01T15:07:05+00:00Added an answer on June 1, 2026 at 3:07 pm

    Turns out it was a missing semi-colon. I need a semi-colon before the regex pattern otherwise it gives syntax error.

    I was running this in Firebug console, which automatically returns the value of the last line… but because there is no semi-colon after the third line, and the fourth starts with a regex, it was getting an error.

    RegExp.prototype.xtend = function(){ console.log(123) }
    y = new RegExp(/pattern/)
    y.xtend()
    /pattern/.xtend()
    

    Adding the semi-colon solves the problem…

    RegExp.prototype.xtend = function(){ console.log(123) }
    y = new RegExp(/pattern/)
    y.xtend(); // <~~ this semi-colon fixes the issue
    /pattern/.xtend()
    

    Thanks for all the comments. Works great now.

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