Question

I know I can pass a method like this:

Class A:
public void foo(Action<Class, Class, Class> bar)
{
    Class a;
    Class b;
    Class c;
    bar(a, b, c);
}
Class B:
public main()
{
    foo(bar);
}
protected void bar(Class a, Class b, Class c);

But I want it to be more conditional:

Class A:
public void foo(bar) {
    Class a;
    Class b;
    Class c;
    Class d;
    if(condition A)
        bar(a, b, c);
    else
        bar(a, b, c, d);
}
Class B:
public main()
{
    foo(bar);
}
protected void bar(Class a, Class b, Class c);
protected void bar(Class a, Class b, Class c, Class d);

How do I do this?

Answer 1

There is no way of passing a method-group (a set of methods of the same name but with different signatures) except by-name as a string, and then using reflection. Any Delegate / Expression / MethodInfo representation must be to a single method.

So: you cannot.

---

Suggestion:

interface IBar {
    void bar(Class a, Class b, Class c);
    void bar(Class a, Class b, Class c, Class d);
}
class YourType : IBar {
    void IBar.bar(Class a, Class b, Class c) {...}
    void IBar.bar(Class a, Class b, Class c, Class d) {...}
    ...
    public main()
    {
        foo(this);
    }
}