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Home/ Questions/Q 193699
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:31:57+00:00 2026-05-11T16:31:57+00:00

I know, I know , this sounds soo easy. But I can’t seem to

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I know, I know, this sounds soo easy. But I can’t seem to find the correct answer on the Internet.

One of the solution I found was to use is_dir.

if(is_dir($dir))
  echo 'directory exists';
else
  echo 'drectory not exist';

But this is wrong— All this function does is to check whether the $dir is a directory, it doesn’t check whether the directory exists, or not. In other words if I put:

$rootDir = "C:\\Documents and Settings\\test\\My Documents\\Image Directory\\Me Dog\\";

then the function will return a true, even though you can find no such directory on your web server.

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:31:57+00:00Added an answer on May 11, 2026 at 4:31 pm

    Should work correctly. From is_dir() documentation:

    Returns TRUE if the filename exists
    and is a directory
    , FALSE
    otherwise.

    Well, anyway if it doesn’t try this:

    if(file_exists($dir) && is_dir($dir))
    

    BTW. results of these functions are cached in stat cache. Use clearstatcache() to clean that cache.

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