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Home/ Questions/Q 9005657
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T01:12:13+00:00 2026-06-16T01:12:13+00:00

I know I will be punished after asking this, still I’d like to do

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I know I will be punished after asking this, still I’d like to do something like this:

#define DEF_CLASS(x) \ 
  #define CLASS x \
  #define CONSTRUCTOR CLASS::CLASS \
  #define COPY_CONSTRUCTOR(x) CONSTRUCTOR(const CLASS& x)

That is I’d like to have a “#define” function which dynamically defines other “#defines”.

I have an IDE which is not capable of refactoring, furthermore I’d like to make constructors, especially copy constructor to stand out due to its special role.
Therefore I aim to program my c++ class definitions like this:

CONSTRUCTOR(int i):i(i){}
COPY_CONSTRUCTOR(other):i(other.i){}
void CLASS::fun1()
{
  //...
}

For that, currently I need to copy&paste three #define lines. I would rather do those automatically. Is there any way to pull this off using the preprocessor?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T01:12:15+00:00Added an answer on June 16, 2026 at 1:12 am

    No, such a DEF_CLASS(x) macro is not possible. Macros aren’t stateful. The best you can do is:

    #define CONSTRUCTOR CLASS::CLASS
    #define COPY_CONSTRUCTOR(x) CONSTRUCTOR(const CLASS& x)
    
    ...
    
    #define CLASS X
        CONSTRUCTOR(int i):i(i){}
        COPY_CONSTRUCTOR(other):i(other.i){}
        void CLASS::fun1()
        {
          //...
        }
    #undef CLASS
    
    #define CLASS Y
        CONSTRUCTOR(int i):i(i){}
        COPY_CONSTRUCTOR(other):i(other.i){}
        void CLASS::fun1()
        {
          //...
        }
    #undef CLASS
    

    But I strongly urge you not to abuse the preprocessor like this. Why obfuscate the normal C++ syntax with these macros? Accept C++ for what it is; don’t try to make it into a different, friendlier language.

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