Question

I Know in jQuery ajax there is tools to detect error but that I want is how to describe what is the problem? 404, no internet connection, internal server error or something else?

This is my simple program

<script type="text/javascript" charset="utf-8" src="http://jquery.local/jquery-1.7.2.min.js"></script>

<script>
    function Create_new_event ()
    {
        url = "missing.php";

        $.post(url, {
        }, function(hasil) {
            alert (hasil);
        });
    }

    $(document).ajaxError(function(event, request, settings) {
        // I believe in this area I should put my code to detect problem
    });

</script>

<button onClick="Create_new_event ();">Send</button>

Answer 1

Yes you can achieve that with thrownError param, do this: http://jsfiddle.net/XJ7L2/

 function Create_new_event() {
   url = "missing.php";

   $.post(url, {}, function (hasil) {
       alert(hasil);
   });
 }
 $(function () {
   $('button').click(function(){
     Create_new_event();
   });
   $(document).ajaxError(function (event, request, settings, thrownError) {
     console.log(request.status  + ' : ' + thrownError);
   });
 });

When an HTTP error occurs, thrownError receives the textual portion of the HTTP status, such as "Not Found" or "Internal Server Error."