Question

I know it sounds awefully confusing, I have a base template class which has a function pointer, a child class(which is no longer a template class) needs to use that function pointer to point to a child class’s member function, and I get all kinds of errors.. Did I violate some universal law of C++?
here is the pseudo code:

template <class T>
class Base{
    public:
       typedef void (Base<T>::*fptr) (char in);
       void funcA(fptr FuncToCall){
                 FuncToCall('a');
       }
       ...
    };

class Child:public Base<char>{
   public: 
       void funcToCall(){...}
       void funcB(){
          funcA(funcToCall);
       }
}

Here is the error message I got:

error C2664: ‘Base< T >::funcA’ : cannot
convert parameter 1 from ‘void
(__thiscall Child::* )(char)’ to ‘void
(__thiscall Base< T >::* )(char)’

Answer 1

Your code is invalid.

Firstly, in C++ to create a pointer to a member function you always have to use operator & and a qualified-name of the member, which means that your call to funcA should look as follows

funcA(&Child::funcToCall); // close, but not yet, see "secondly" 

Secondly, member pointers are contravariant. If want to initialize a base-member pointer object with a derived-member pointer value, you have to use an explicit static_cast

funcA(static_cast<fptr>(&Child::funcToCall));

Note that this is a valid, but potentially unsafe conversion, since it is now your responsibility to ensure that the actual object used on the left-hand side of the call (see “thirdly”) has that member.

Thirdly, in order to call a function through such a pointer, you have to supply a concrete object on the left-hand side, so the call in funcA should look as follows (I assume that you want to call it for *this object)

(this->*FuncToCall)('a');

Fourthly, your funcToCall is supposed to have a parameter. Where is it?