Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 770249
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T18:28:07+00:00 2026-05-14T18:28:07+00:00

I know little of optimization problems, so hopefully this will be didactic for me:

  • 0

I know little of optimization problems, so hopefully this will be didactic for me:

rotors = [1, 2, 3, 4...]
widgets = ['a', 'b', 'c', 'd' ...]

assert len(rotors) == len(widgets)

part_values = [
(1, 'a', 34),
(1, 'b', 26),
(1, 'c', 11),
(1, 'd', 8),
(2, 'a', 5),
(2, 'b', 17),
....
]

Given a fixed number of widgets and a fixed number of rotors, how can you get a series of widget-rotor pairs that maximizes the total value where each widget and rotor can only be used once?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T18:28:08+00:00Added an answer on May 14, 2026 at 6:28 pm

    What you have is a maximum weighted bipartite matching problem: on the left, you have widgets, on the right, rotors, and the weights of the connections are the point values. This Wikipedia article goes into how to solve it.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I know very little about JavaScript but despite this I'm trying to cobble something
This works, but it was a stab in the dark. I know little Ruby.
I know a little about SNMP, but not enough. I need to develop an
I know very little about Flash, and so is not programming in it. I
I know a little bit of regex, but not mutch. What is the best
First question on here so please be nice :) I know very little about
I'm an absolute noob at iPhone development but I know a little C. I
The code here is X++. I know very little about it, though I am
I am new to Perl, but I know a little bit of C though.
I just started thinking about creating/customizing a web crawler today, and know very little

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.