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Home/ Questions/Q 8751897
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T13:07:57+00:00 2026-06-13T13:07:57+00:00

I know of 2 ways to dynamically allocate memory. I understand how new works,

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I know of 2 ways to dynamically allocate memory. I understand how “new” works, but I don’t understand how “static cast” works:

double* A1;
double** A2;

//1D array
A_1 = new double[size];

A_1 = static_cast <double*> (new double[c]);

//2D array
A_2 = reinterpret_cast <double**> (new double[r]);
for(i = 0; i < r; i++)
    A_2[i] = static_cast <double*> (new double[c]);

I don’t understand how static and reinterpret are working.

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  1. Editorial Team
    Editorial Team
    2026-06-13T13:07:58+00:00Added an answer on June 13, 2026 at 1:07 pm

    While new is the keyword for allocating a new object, static_cast and reinterpret_cast serve a different purpose and, as others have pointed out by now, do not allocate memory.

    A short explanation is that static_cast converts between pointers to compatible classes or between compatible non-pointer types. So you could cast a Vehicle pointer to a Car pointer or the other way around, but there is no check at runtime that your Vehicle is actually a Car when you cast it. dynamic_cast on the other hand features a runtime check.

    reinterpret_cast simply converts the pointer even if the types are not compatible.

    There are plenty of resources where you can find a more in-depth explanation, like http://www.cplusplus.com/doc/tutorial/typecasting/

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