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Home/ Questions/Q 6604981
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:13:44+00:00 2026-05-25T19:13:44+00:00

I know segmentation fault means that the process has attempted to access certain memory

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I know segmentation fault means that the process has attempted to access certain memory that it’s not allowed to.

I’m running some program written by others using C++. And when my input is large (around 1GB), there’ll be a segmentation fault even though I requested 30GB memory; while when input size is quite small, it goes well.

So what shall I do? Is it because there’s not enough memory? I’m really kind of a newbie without much knowledge of C++. I don’t even know which part of the code controls memory allocation.

Thanks to BLender, line from the debugging is:

Program received signal SIGSEGV, Segmentation fault.
0x0000003fbd653174 in _IO_vfscanf_internal ()
from /share/bin/intel/cc/10.1.015/lib/tls/x86_64/libc.so.6

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:13:45+00:00Added an answer on May 25, 2026 at 7:13 pm

    Your code calls malloc several times, but never free, so it uses quite a lot of memory. And it never checks for an out-of-memory condition…

    My suggestion is that you change all the calls to malloc to something like:

    size_t total_memory = 0;
    void *my_malloc(size_t sz)
    {
        void *res = malloc(sz);
        total_memory += sz;
        if (res == NULL)
        {
            printf("Too much memory eaten: %zu\n", total_memory);
            abort();
        }
        return res;
    }
    #define malloc(x) my_malloc(x)
    

    And see what happens.

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