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Home/ Questions/Q 3723376
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T06:14:52+00:00 2026-05-19T06:14:52+00:00

I know that I can do the following [^h] to get all matches accept

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I know that I can do the following [^h] to get all matches accept the ones with a ‘h’.
How would I do this with an entire word, like ^(word)

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  1. Editorial Team
    Editorial Team
    2026-05-19T06:14:53+00:00Added an answer on May 19, 2026 at 6:14 am

    If you want to match a string that is not identical to foo:

    ^(?!foo).*$
    

    If you want to match a string that does not contain foo:

    ^(?!.*foo).*$
    

    If you want to match a string that does not contain foo as a complete word:

    ^(?!.*\bfoo\b).*$
    

    If you want to match a string until foo appears and stop the match before foo:

    ^(?:(?!foo).)*
    

    These solutions do not handle newlines in the string, so you might have to set the corresponding regex options like RegexOptions.Singleline in .NET if that’s a problem.

    (?!foo) is a zero-width negative lookahead expression, meaning that it asserts that it is not possible (“negative”) to match foo following the current position in the string (“look ahead“), while not consuming any characters in the match attempt (“zero-width”).

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