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Home/ Questions/Q 7218237
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T21:27:25+00:00 2026-05-28T21:27:25+00:00

I know that I can use the following to have thread B waiting for

  • 0

I know that I can use the following to have thread B waiting for thread A to finish before proceeding:

class A extends Thread{
    public void run(){
        ....
    }
}
class B extends Thread{
    private Thread someThread;
    B(Thread t){
        someThread=t;
    }
    public void run(){
        someThread.join();
        ...//then proceed
    }
}

But how can I do this in the run() of A to call B and then wait it finish before proceeding? That is, I want something like

class A extends Thread{
    private Thread someThread;
    B(Thread t){
        someThread=t;
    }
    public void run(){
        //*how to start B and wait it finish?
        ...//then proceed
    }
}
class B extends Thread{
    public void run(){
        ....
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T21:27:25+00:00Added an answer on May 28, 2026 at 9:27 pm

    If possible, a simpler solution would be to start B first, then b.join();, and do the same for A in the client code:

    b.start();
    b.join();
    a.start();
    a.join();
    

    There is no sense in starting a thread for it to just fire up and join on another tread before proceeding.

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