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Home/ Questions/Q 6848445
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:52:09+00:00 2026-05-27T00:52:09+00:00

I know that in C, arrays are not supposed to be dynamically sized. With

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I know that in C, arrays are not supposed to be dynamically sized.

With that in mind, would the following code be allowed? (Trying to declare an array of chars the same length as a double.)

char bytes[sizeof(double)];

My guess is that sizeof operates on its argument during program execution and so this wouldn’t be allowed, but I’m not sure.

Also, would there be a difference if this were C++ instead of C?

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:52:10+00:00Added an answer on May 27, 2026 at 12:52 am

    The sizeof expression is evaluated at compile time (by the compiler not the preprocessor) so the expression is legal.

    There’s an exception to this rule in C99 where dynamic arrays are allowed. In that case sizeof is, depending on context, evaluated at runtime (http://en.wikipedia.org/wiki/Sizeof). It doesn’t change the legality of the expression in the question.

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