I know that the access specifier visibility of the overridden method/property must be the same or above as that of the base method/property and I also know that the visibility of members of interfaces is public by default. So how and why can the visibility of the members be private when we implement the interface explicitly in a class though those private methods can be accessed by casting the class object to the implemented interface?
public interface IRocker
{
string RockOff(string str);
}
public abstract class AmAbstract
{
public abstract string SomeMethod(string str);
}
class Program : AmAbstract, IRocker
{
static void Main(string[] args)
{
new Hello().RockU();
Console.ReadKey();
}
string IRocker.RockOff(string str)
{
return str;
}
public override string SomeMethod(string str)
{
return str;
}
}
public class Hello
{
public void RockU()
{
Console.WriteLine(((IRocker)(new Program())).RockOff("Damn"));
Console.WriteLine(((AmAbstract)(new Program())).SomeMethod("lalalalala"));
}
}
‘Console.WriteLine(((IRocker)(new Program())).RockOff(“Damn”));’ statement shows us ultimately accessing a private method of the class ‘Program’. My question is why we can’t hide the visibility of an abstract method as we can with an interface method? And why we are able to access private method through interface? Any help will be highly appreciated.
You are using explicit interface implementation when implementing
IRocker.RockOff(). There are separate rules for those in C#, and in fact these are kind of private and public at the same time.A quote from paragraph 13.4.1 of the C# 4.0 specification:
There are no such exceptions for abstract classes, so just the regular modifier rules apply.