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Home/ Questions/Q 3310410
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T21:45:25+00:00 2026-05-17T21:45:25+00:00

I know that the C++ standard explicitly guarantees the size of only char ,

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I know that the C++ standard explicitly guarantees the size of only char, signed char and unsigned char. Also it gives guarantees that, say, short is at least as big as char, int as big as short etc. But no explicit guarantees about absolute value of, say, sizeof(int). This was the info in my head and I lived happily with it. Some time ago, however, I came across a comment in SO (can’t find it) that in C long is guaranteed to be at least 4 bytes, and that requirement is “inherited” by C++. Is that the case? If so, what other implicit guarantees do we have for the sizes of arithmetic types in C++? Please note that I am absolutely not interested in practical guarantees across different platforms in this question, just theoretical ones.

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:45:26+00:00Added an answer on May 17, 2026 at 9:45 pm

    18.2.2 guarantees that <climits> has the same contents as the C library header <limits.h>.

    The ISO C90 standard is tricky to get hold of, which is a shame considering that C++ relies on it, but the section “Numerical limits” (numbered 2.2.4.2 in a random draft I tracked down on one occasion and have lying around) gives minimum values for the INT_MAX etc. constants in <limits.h>. For example ULONG_MAX must be at least 4294967295, from which we deduce that the width of long is at least 32 bits.

    There are similar restrictions in the C99 standard, but of course those aren’t the ones referenced by C++03.

    This does not guarantee that long is at least 4 bytes, since in C and C++ “byte” is basically defined to mean “char”, and it is not guaranteed that CHAR_BIT is 8 in C or C++. CHAR_BIT == 8 is guaranteed by both POSIX and Windows.

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