I know that there is a library that do that
use Scalar::Util qw(looks_like_number);
yet I want to do it using perl regular expression. And I want it to work for double numbers not for only integers.
so I want something better than this
$var =~ /^[+-]?\d+$/
thanks.
Constructing a single regular expression to validate a number is really difficult. There simply are too many criteria to consider. Perlfaq4 contains a section “How do I determine whether a scalar is a number/whole/integer/float?
The code from that documentation shows the following tests:
So if you were using those tests (excluding the first one) you would have to verify that one or more of the tests passes. Then you’ve got a number.
Another method, since you don’t want to use the module Scalar::Util, you can learn from the code IN Scalar::Util. The looks_like_number() function is set up like this:
You should be able to use the portions of that function that are applicable to your situation.
I would like to point out, however, that
Scalar::Utilis a core Perl module; it ships with Perl, just likestrictdoes. The best practice of all is probably to just use it.