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Home/ Questions/Q 9312961
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Editorial Team
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Editorial Team
Asked: June 19, 20262026-06-19T01:45:42+00:00 2026-06-19T01:45:42+00:00

I know that using the static keyword in C on a function restricts the

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I know that using the static keyword in C on a function restricts the function to the compilation unit in which it is defined. I am now looking into symbol visibility, and I’m a little confused about the difference between static functions and function marked with __attribute__((visibility("hidden"))), or using the -fvisibility=hidden command-line option.

I have a feeling that the way these change things under-the-hood is not at all the same, but I don’t know what the difference is nor what it implies when working with them in actual code. What changes between the two, and when would you want to use one over the other?

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  1. Editorial Team
    Editorial Team
    2026-06-19T01:45:44+00:00Added an answer on June 19, 2026 at 1:45 am

    A function with __attribute__((visibility("hidden"))) is not visible outside the shared library containing it, but if that library was made by linking foo.pic.o and bar.pic.o such a function fhid can be defined in foo.c and called from bar.c. Of course outside code (e.g. from the main program or some other shared library) cannot call that fhid

    So hidden visibility applies to an entire shared library, not to individual compilation units composing it.

    In contrast, it would have been possible for foo.c to define a static void fsta(void) function, and for bar.c to define a different static void fsta(void) function (even if that is poor taste and should be avoided for readability reasons).

    Also, in principle, a static function could be more easily inlined, or the compiler could (sometimes) use different calling conventions for it.

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