Question

I know that when passing strings between functions

char *str is almost the same as char str[n] in function header.

However i do wanna know why this would work and whats the difference between these 2 when working with string

I found that if i declare a “char *in” first then assign a string to it “in=string;”
this wont work

can some one tell me whats behind this?

Is there anyway I can assign a array to another array? like in Java

Thanks

char[] one;
char[] two={'a','b'};
one=two;

Answer 1

char[] one;

The syntax is wrong. This isn’t Java.

char* one;
char two[]={'a','b'};
one = two;

This works because array decays to a pointer.

“char *str is almost the same as char str[n] in function header.”

NO. Arrays and pointers are two different concepts. They both aren’t the same.