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Home/ Questions/Q 8502085
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T01:23:15+00:00 2026-06-11T01:23:15+00:00

I know that when you call a function this way : foo(MyClass a) The

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I know that when you call a function this way :

foo(MyClass a)

The object a is being passed by value meaning it’s being copied.

My question is how is it being copied?
say my class don’t have a copy constructor, so if it is passed using shallow copy than
the object may change inside the function?

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  1. Editorial Team
    Editorial Team
    2026-06-11T01:23:17+00:00Added an answer on June 11, 2026 at 1:23 am

    Compiler automatically generates the code for the copy constructor and performs member wise copy. The copy constructor which compiler calls does member wise copy which is indeed shallow copy.

    It is inadvisable to pass an object by value if a pointer in your class exists. Even if a pointer does not exist, but a dozen other data members exist, they would require a lot of time to get copied.Pass it by reference, and make it const if you dont want its value to be changed.

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