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Home/ Questions/Q 4055914
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T14:45:40+00:00 2026-05-20T14:45:40+00:00

I know the following code would show a loading image when a button is

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I know the following code would show a loading image when a button is clicked on the page:

   $.ajaxSetup ({  
         cache: false  
     });  
     var ajax_load = "<img src='img/load.gif' alt='loading...' />";  


     var loadUrl = "ajax/load.php";  
     $("#load_basic").click(function(){  
         $("#result").html(ajax_load).load(loadUrl);  
     });

but what if I want this to happen soon as the page loads. I dont want the user interaction of clicking a button to make the ajax call.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T14:45:40+00:00Added an answer on May 20, 2026 at 2:45 pm

    Throw it inside the document ready function:

    $(document).ready(function() {
    $.ajaxSetup ({  
         cache: false  
     });  
     var ajax_load = "<img src='img/load.gif' alt='loading...' />";  
     var loadUrl = "ajax/load.php";   
     $("#result").html(ajax_load).load(loadUrl);  
    }
    
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