Question

I know the problem has been addressed a million times here, and I know it’s about the typesafety (or rather lack of it) of printf, but I would like some help with the fix since the prof completely refuses C++ solutions.
I have the following structure:

struct node  
{  
        char author[40];  
        char title[40];  
        float price;  
        int stock;  
        nod *next;          
};

I know for a fact that the info is properly stored and I’ve narrowed the problem down to the displaying function:

void display()                      
{    
   nod *nod;    
   nod=p;                           
   while(nod)                       
   {    
      printf("%s \t %s \t %e \t%d", &node->auhtor, &node->title, &node->price, &node->stock);         
      node=node->next;}                
      printf("\n");    
   }    
}    

What exactly do I need to change for it to display the same results as

cout<<nod->autor<<'\t'<<nod->titlu<<'\t'<<nod->pret<<'\t'<<nod->stoc<<endl;

Answer 1

Just remove all the ampersands. You want the real deal, so don’t apply the reference operator.