Question

I know there is a way to block or now show context menu by using ContextMenuOpening event.

But I still want to show the context menu, just disable everything in it, is there a way to do it?

How can I disable all the menu item at a same time?

<DataTemplate x:Key="ItemDataTemplate">
    <Grid Background="Transparent">
        <Grid.ContextMenu>
            <ContextMenu>
                <MenuItem Header="New" Click="New_Click" />
                <Separator />
                <MenuItem Header="Duplicate" Click="Duplicate_Click"/>
                <MenuItem Header="Delete" Click="Delete_Click"  />
                <MenuItem Header="Rename" Click="Rename_Click" />
                <Separator />
                <MenuItem Header="Export..." Click="Export_Click" />
                <MenuItem Header="Print..."
                          Command="ApplicationCommands.Print"
                          InputGestureText="" />
                <Separator />
                <MenuItem Header="Properties" Click="Properties_Click" />
            </ContextMenu>
        </Grid.ContextMenu>
        <StackPanel Orientation="Horizontal"
                    Margin="0,0,10,0"
                    HorizontalAlignment="Stretch"
                    Background="Transparent"
                    IsHitTestVisible="False">    
        </StackPanel>
    </Grid>    
</DataTemplate>

Answer 1

Here is how I solve my question.

Still use ContextMenuOpening event. Use a loop.

This why can help me disable certain context menu item in code, but not in XAML.

private void SetContextMenuItemsEnableStatus(object sender)
{
    FrameworkElement element = sender as FrameworkElement;
    if (element == null)
    {
        return;
    }
    ContextMenu contextMenu = element.ContextMenu;          
    if (contextMenu == null)
        return;
    //Use this way.
    //You can disable every item or certain item in context menu.
    foreach (Control item in contextMenu.Items)
    {
        item.IsEnabled = false;
    }
 }