Question

I know theres a method_exists() but it says true even when that method is inherited.

class A
{
 public function eix()
 {
 }
}

class B extends A
{
}

echo method_exists (‘B’, ‘eix’);

so its true, but B class doesnt have it. How to dodge this?

Answer 1

You’ll need to use reflection to achieve this. Look into the ReflectionMethod class and you’ll find the getDeclaringClass method.

$classname = 'B';
$methodname = 'eix';

$method = new ReflectionMethod($classname, $methodname);
$declaringclass = $method->getDeclaringClass();

if ($classname == $declaringclass->name) {
    // method was defined on the original class
}

That said, the key point is that class B does have a method eix, since it inherits all A‘s methods that it doesn’t redefine. I can’t quite work out a circumstance where you’d need to know where the method was defined, but this technique allows you to do so if necessary.