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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T20:36:43+00:00 2026-05-23T20:36:43+00:00

I know these questions are lame and make Stack Overflow like a regex dictionary,

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I know these questions are lame and make Stack Overflow like a regex dictionary, but I really would need some help with. It’s like trying to understand hieroglyphs (at least for someone this is easy reputation).

I want to write a regex to check if password is at least 8 characters long and has at least 2 numbers or symbols (or mixed). The symbols probably can be the obvious ones [-+_!@#$%^&*.,?].

So I’ve come up with something like this so far: ^(?=.{8,})(?=.*\d{2,}).*$, but I can’t understand how to put the symbols sequence in the \d part. Oh, I’m not sure if (?=) does work for Java, does it? This rubular.com/r/VC0ncbDlRl made writing regex little easier.

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  1. Editorial Team
    Editorial Team
    2026-05-23T20:36:44+00:00Added an answer on May 23, 2026 at 8:36 pm

    That is not a job to do with a RegEx. In Java, it is so much simpler to write some custom code:

    public static boolean isValidPassword(String pass)
    {
        if (pass.length() < 8) return false;
    
        int symbolOrNumberCount = 0;
        String symbols = "0123456789-+_!@#$%^&*.,?";
    
        for (int i = 0; i < pass.length(); ++i)
        {
            if (symbols.indexOf((int) pass.charAt(i)) != -1)
            {
                symbolOrNumberCount++;
            }
        }
    
        return symbolOrNumberCount >= 2;
    }
    
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