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Asked: May 11, 20262026-05-11T04:20:10+00:00 2026-05-11T04:20:10+00:00

I know this is a darn simple question, but I’m very used to using

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I know this is a darn simple question, but I’m very used to using Borland and wrappers, so this is a bit of a new approach for me. Can someone simply tell me how I Can open an OpenDialog that only gets .obj files from a visual studio c++ console app?

It’s very much appreciated!

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  1. 2026-05-11T04:20:10+00:00Added an answer on May 11, 2026 at 4:20 am

    There isn’t really any difference between a console application and a GUI application, except for entry point (WinMain in a ‘GUI’ app), and a console app will have a console window opened during startup if not started from a console.

    All of the Win32 API is available, so you need to use the GetOpenFileName call, as follows:

    #define DEFAULT_EXTENSION L".obj"

    OPENFILENAME    ofn; wchar_t *FilterSpec =L"Object Files(*.obj)\0*.obj\0Text Files(*.txt)\0*.txt\0All Files(*.*)\0*.*\0"; wchar_t *Title =L"Open...."; wchar_t szFileName[MAX_PATH]; wchar_t szFileTitle[MAX_PATH]; int             Result; wchar_t filePath[MAX_PATH]; // Selected file and path  *szFileName = 0; *szFileTitle = 0;  /* fill in non-variant fields of OPENFILENAME struct. */ ofn.lStructSize       = sizeof(OPENFILENAME); ofn.hwndOwner         = GetFocus(); ofn.lpstrFilter       = FilterSpec; ofn.lpstrCustomFilter = NULL; ofn.nMaxCustFilter    = 0; ofn.nFilterIndex      = 0; ofn.lpstrFile         = szFileName; ofn.nMaxFile          = MAX_PATH; ofn.lpstrInitialDir   = L"."; // Initial directory. ofn.lpstrFileTitle    = szFileTitle; ofn.nMaxFileTitle     = MAX_PATH; ofn.lpstrTitle        = Title; ofn.lpstrDefExt   =     DEFAULT_EXTENSION;  ofn.Flags             = OFN_FILEMUSTEXIST|OFN_HIDEREADONLY;  if (!GetOpenFileName ((LPOPENFILENAME)&ofn)) {     return; // Failed or cancelled } else {     wcscpy_s(filePath,ofn.lpstrFile); } 
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