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Home/ Questions/Q 6385359
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T02:53:21+00:00 2026-05-25T02:53:21+00:00

I know this is an artificially complicated example, but why are both PIDs the

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I know this is an artificially complicated example, but why are both PIDs the same in the first line, while (as expected, to me at least) the two other lines yield different PIDs?

$ sh -c 'sh -c "echo $$ \$\$"'
4500 4500
$ sh -c 'sh -c "echo $$ \$\$"; true'
4596 5060
$ sh -c 'true; sh -c "echo $$ \$\$"'
4728 2868

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-25T02:53:22+00:00Added an answer on May 25, 2026 at 2:53 am

    For me in bash 4.1.5, the output of first line is:

    sh -c 'sh -c "echo $$ \$\$"'
    4063 4064
    

    as expected – values are different.
    Also tested on ash, sh, and zsh.

    It must be some tricky optimization.

    Update:

    in bash 3.2 there is and “ONESHOT” feature:
    see comment in the shell.c:1243:

    #if defined (ONESHOT)
    /* Run one command, given as the argument to the -c option.  Tell
    parse_and_execute not to fork for a simple command. */
    
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