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Home/ Questions/Q 7878721
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T03:44:19+00:00 2026-06-03T03:44:19+00:00

I know this is probably really dumb, but I can’t figure out why this

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I know this is probably really dumb, but I can’t figure out why this if statement is failing:

If I enter 1 or 2 at the console, the first if statement fails, but the second one passes if I first store the result in a bool first. Why? I am probably doing something dumb here?

Console.WriteLine("Enter 1 for AM or 2 for PM?"); 
string amOrPM = Console.ReadLine();

//Why does this fail if I enter 1 or 2?
if (amOrPM != "1" || amOrPM != "2") 
    Console.WriteLine("You must enter 1 for AM or 2 for PM. Try again.");

//This works!
bool valid = (amOrPM != "1" || amOrPM != "2"); 
if (!valid) 
    Console.WriteLine("You must enter 1 for AM or 2 for PM. Try again.");

I just noticed for the first if statement, I had to put && instead of ||, but this is confusing because I read it as: if amOrPm does not equal 1 or amOrPM does not equal 2, then go to the Console line. Am I reading the definition of this wrong?

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  1. Editorial Team
    Editorial Team
    2026-06-03T03:44:20+00:00Added an answer on June 3, 2026 at 3:44 am

    Think of it this way – if it is 1, then it can’t possibly be 2, and vice versa. So it will definitely be either “not 1” or “not 2”.

    You mean:

    if (amOrPM != "1" && amOrPM != "2") 
    

    (If it’s “not 1” and it’s “not 2”.)

    Or:

    if (!(amOrPm == "1" || amOrPm == "2"))
    

    See De Morgan’s Laws for more transformations.

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