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Home/ Questions/Q 4555824
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T17:16:48+00:00 2026-05-21T17:16:48+00:00

I know this is stupid but I’m a quiet a noob in a programming

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I know this is stupid but I’m a quiet a noob in a programming world here is my code.

This one works perfectly:

#include <stdio.h>

int main() {

    float x = 3153600000 ;

    printf("%f", x);

    return 0;
}

But this one has a problem:

#include <stdio.h>

int main() {

    float x = 60 * 60 * 24 * 365 * 100 ;

    printf("%f", x);

    return 0;
} 

So 60 * 60 * 24 * 365 * 100 is 3153600000 right ??? if yes then why does it produced different results ??? I got the overflow in the second one it printed “-1141367296.000000” as a result. Could anyone tell me why ?

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  1. Editorial Team
    Editorial Team
    2026-05-21T17:16:49+00:00Added an answer on May 21, 2026 at 5:16 pm

    You’re multiplying integers, then putting the result in a float. By that time, it has already overflowed.

    Try float x = 60.0f * 60.0f * 24.0f * 365.0f * 100.0f;. You should get the result you want.

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