Question

I know this may be a duplicate, but I cant wrap my brain around the other examples. Help would be appreciated.
I have a php array that i need to assign to a javascript array. Here is my amateur way of doing it now.
You can see source at http://www.preferweb.com/accentps/index.php

<?php

$i=0;
while ($result1 = mysql_fetch_array($query1)){
print "<script>";
print "var size[".$i."]=" .$result1['type'].";\n";
print "var 25[".$i."]=" .$result1['25'].";\n";
print "var 50[".$i."]=" .$result1['50'].";\n";
print "var 100[".$i."]=" .$result1['100'].";\n";
print "var 250[".$i."]=" .$result1['250'].";\n";
print "var 500[".$i."]=" .$result1['500'].";\n";
print "var plus[".$i."]=" .$result1['plus'].";\n";
$i = $i+1;
}
print "var tick='1';\n";
print "alert (tick);\n";
print "</script>\n";
?>
<script>
alert (500[0]);

</script>

This alerts undefined for the tick alert and nothing for the second alert.. Thanks..

Answer 1

You cannot use an integer as a variable name, like in this line: print "var 25[".$i."]=" .$result1['25'].";\n";. 25 cannot be a variable.

If you want to map an array to a javascript object, you might want to take a look at json_encode

EXAMPLE
Your code could be written like this:

<?php
$result = array();

while ($row = mysql_fetch_array($query1)){
  $result[] = $row;
}
?>
<script>
  var result = <?= json_encode($result); ?>;
  alert (result[1][500]);
</script>

looks much cleaner to me.