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Home/ Questions/Q 9265693
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T14:08:14+00:00 2026-06-18T14:08:14+00:00

I know this question has been asked before, but either the answers don’t apply

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I know this question has been asked before, but either the answers don’t apply to this case, or I don’t understand them.

Basically, why doesn’t the following (simple example that recreates my problem) work ?

class Test[+T] {
    var list: List[T] = _
}

The problem I am having is that I have an object, where I want to pass in an instance of Test[Nothing] (the empty Test), and this doesn’t work unless I make Test co-variant in T.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T14:08:16+00:00Added an answer on June 18, 2026 at 2:08 pm

    Making test covariant in T means that Test[A] is a subtype of Test[Any] for any A. So lets create a Test:

    val test_string = new Test[String]
    

    Now we have a Test[String] and the contained list is type List[String].

    Since Test[String] is a subtype of Test[Any], the following should be allowed:

    val test_any : Test[Any] = test_string
    

    And now, we have a Test[Any], and therefore test_any.list is type List[Any], which means the following should be valid:

    test_any.list = List[Any]()
    

    Which means we just assigned a List[Any] to test_strings list member, which shouldn’t be allowed, since that is supposed to be a List[String], not a List[Any]. It also means you could prepend anything at all to the list, since it is type List[Any].

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