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Home/ Questions/Q 4623346
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:58:26+00:00 2026-05-22T02:58:26+00:00

I know this question is not new but I am posting this after going

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I know this question is not new but I am posting this after going through enough googling around.

I have a jar file which I don’t control. I mean I have not written the Java class in there and all I know is that there is a class named “hist” in it which takes two arrays and gives out the output. Now I have to use PHP to call this class “hist” in the jar file named “histvol.jar”. I have installed the PHP/Java Bridge and it is installed correctly.
But I don’t understand how to call this jar file in PHP and where to place this jar file.

This is what I did:

  1. Installed tomcat and php-javabridge
  2. Placed the jarfile “histvol.jar” under Tomcat/webapps/JavaBridgeTemplate621/webinf/lib/
  3. Went to xampp/htdocs and created a file named testjava.php
<?php  
require_once("http://localhost:8080/JavaBridgeTemplate621/java/Java.inc");  
$System = java("java.lang.System");  
$myclass=java("histvol");  
echo $System->getProperties();  
?>

Class not found exception is expected because I am not calling it anywhere in PHP, but how do I call it?
I am lost, please help (I don’t know a word of Java).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:58:27+00:00Added an answer on May 22, 2026 at 2:58 am

    Ok I got it finally, I just had to do this:-

    $myclass=new java("histvolone.histvol");
    

    instead of

    $myclass=new java("histvol");
    

    It worked !

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