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Home/ Questions/Q 6542947
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:17:14+00:00 2026-05-25T11:17:14+00:00

I know you can do something like: def.h: A(); int x; A.h class A

  • 0

I know you can do something like:

def.h:

A();
int x;

A.h

class A
{
public:
#include "def.h"
}

A.cpp

A::A()
{
    x = 0;
}

int main()
{
    A a;
    return 0;
}

My questions is: why would you do this? Are there any advantages? I can see how it would be helpful if you have some classes with the same members but not the same base, but is it worth the hassle? It’s not very readable, is it?
Also, how does the compiler treat these includes? Does it just paste the content of the header where it’s included (kind of like a macro)?

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:17:15+00:00Added an answer on May 25, 2026 at 11:17 am

    The preprocessor (which runs before anything), when it stumbles upon an include, almost literally copies the content of that header and pastes it in the place of the #include directive.

    The advantages of using it like you describe are few, the main one being that you don’t have to duplicate code.

    However, in 9999/10000 situations, it is definitely not worth the hassle. If you have a typo somewhere in the header file, you’ll get strange errors in every file that uses it, and it’s not clear at all what it’s doing until you actually open the file and read it.

    Avoid that if at all possible. I can’t think of a situation where it would be absolutely necessary; the same effect can be achieved with inheritance or composition most of the time without all the side-effects.

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