Home/ Questions/Q 6325741
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-24T16:57:12+00:00

I learned to get a linear fit with some points using lm in my

  • 0

I learned to get a linear fit with some points using lm in my R script. So, I did that (which worked nice), and printed out the fit:

lm(formula = y2 ~ x2)

Residuals:
         1          2          3          4 
 5.000e+00 -1.000e+01  5.000e+00  7.327e-15 

Coefficients:
            Estimate Std. Error t value Pr(>|t|)   
(Intercept)   70.000     17.958   3.898  0.05996 . 
x2            85.000      3.873  21.947  0.00207 **
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 

Residual standard error: 8.66 on 2 degrees of freedom
Multiple R-squared: 0.9959, Adjusted R-squared: 0.9938 
F-statistic: 481.7 on 1 and 2 DF,  p-value: 0.00207

I’m trying to determine the best way to judge how great this fit is. I need to compare this fit with a few others (which are also linear using lm() function). What value from this summary would be the best way to judge how good this fit is? I was thinking to use the residual standard error. Any suggestions. Also, how do I extract that value from the fit variable?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    If you want to access the pieces produced by summary directly, you can just call summary and store the result in a variable and then inspect the resulting object:

    rs <- summary(lm1)
names(rs)

    Perhaps rs$sigma is what you’re looking for?

    EDIT

    Before someone chides me, I should point out that for some of this information, this is not the recommended way to access it. Rather you should use the designated extractors like residuals() or coef.

    • 0