Question

I like the way ElementTree parses xml, in particular the Xpath feature. I’ve an output in xml from an application with nested tags.

I’d like to access this tags by name without specifying the namespace, is it possible?
For example:

root.findall("/molpro/job")

instead of:

root.findall("{http://www.molpro.net/schema/molpro2006}molpro/{http://www.molpro.net/schema/molpro2006}job")

Answer 1

At least with lxml2, it’s possible to reduce this overhead somewhat:

root.findall("/n:molpro/n:job",
             namespaces=dict(n="http://www.molpro.net/schema/molpro2006"))