Question

I like to use GSON to deserialize the following JSON String.

{
  "type": "FeatureCollection",
  "features": [
    {
      "id": "FSROGD.4440181",
      "geometry": {
        "type": "Point",
        "coordinates": [
          16.7594706041998,
          43.148716514354945
        ]
      }
    }
  ]
}

I already prepared the neccessary Java classes named Response, Features, Geometry and Coordinates. Besides the last class everything works fine. But for Coordinates, I do not understand what I should write since there are no keys given that I could prepare as member variables.
Here are the parent Geometry class …

package info.metadude.trees.model.vienna;    
import com.google.gson.annotations.SerializedName;

public class Geometry {     
    @SerializedName("type")
    public String type;

    // TODO: Prepare Coordinates class for GSON.
    // @SerializedName("coordinates")
    // public Coordinates coordinates;
}

… and the empty Coordinates class.

package info.metadude.trees.model.vienna;    
public class Coordinates {
    // TODO: No idea what should be defined here.
}

Answer 1

You could use coordinates as a collection property in Geometry. This would automatically map the values to the right property.

import java.util.List;

import com.google.gson.Gson;

public class GSonTest {

    public static void main(final String[] args) {
        Gson gson = new Gson();
        System.out.println(gson.fromJson("{        \"type\": \"Point\",        \"coordinates\": [          16.7594706041998,          43.148716514354945        ]      }", Geometry.class));
    }

    public static class Geometry {

        List<Float> coordinates;

        public List<Float> getCoordinates() {
            return coordinates;
        }

        public void setCoordinates(final List<Float> coordinates) {
            this.coordinates = coordinates;
        }

        @Override
        public String toString() {
            return "Geometry [coordinates=" + coordinates + "]";
        }

    }

}