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Home/ Questions/Q 7399125
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T04:01:04+00:00 2026-05-29T04:01:04+00:00

I looked up in the net, but cannot find any answer (maybe my search

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I looked up in the net, but cannot find any answer (maybe my search term is not accurate)

I want to pass a string parameter in the django url, by using this pattern:

 urlpatterns=('item.views',
    url(r'^receive/find/(?P<key>\s+)/$', 'find'))

For example the passed url will be something line this /item/receive/PO/. But django never recognizes this as the pattern above.

Please take not that the url is decoupled into item app urls

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  1. Editorial Team
    Editorial Team
    2026-05-29T04:01:04+00:00Added an answer on May 29, 2026 at 4:01 am

    In your pattern, \s matches a whitespace character. Try with \w. http://en.wikipedia.org/wiki/Regular_expression#Examples

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