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Home/ Questions/Q 6192345
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T02:55:39+00:00 2026-05-24T02:55:39+00:00

i m calling default map app. from my application but for example when i

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i m calling default map app. from my application but for example when i select Portugal language on my iphone for current location NSURL return nil.
I already used UTF8encoding and percentage encapsulate as follows:-

 NSString *encodedURLString = [urlString stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];
    //where urlString has value http://maps.google.com/maps?saddr=Localiza\u00e7\u00e3o+actual&daddr=28.6522907,77.1929857
 NSURL *URL = [NSURL URLWithString:encodedURLString];
 [[UIApplication sharedApplication] openURL:URL];

i already try NSUTF8Encoding instead NSASCIIStringEncoding but nothing helped.
thanx for any help.

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  1. Editorial Team
    Editorial Team
    2026-05-24T02:55:40+00:00Added an answer on May 24, 2026 at 2:55 am

    You are percent-encoding the entire URL.

    This turns http://www.google.com into http%3A//www.google.com, which is a malformed URL.

    From the NSURL Class Reference:

    Return Value: An NSURL object initialized with URLString. If the string was malformed, returns nil.

    Ergo, you are receiving nil.

    What you want to do is this:

    NSString *path = @"http://maps.google.com/maps";
    NSString *query = @"saddr=Localiza\u00e7\u00e3o+actual&daddr=28.6522907,77.1929857";
    query = [query stringByAddingPercentEscapesUsingEncoding: NSASCIIStringEncoding];
    
    NSString *url = [NSString stringWithFormat: @"%@?%@", path, query];
    NSURL *URL = [NSURL URLWithString: url];
    [[UIApplication sharedApplication] openURL: URL];
    
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