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Home/ Questions/Q 9006685
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T01:28:43+00:00 2026-06-16T01:28:43+00:00

i m using SQL 2008 R2 i got duplicate value from my join table:

  • 0

i m using SQL 2008 R2

i got duplicate value from my join table:
Join Table

SELECT *
FROM LETTRE_VOIT 
 LEFT JOIN FAWEB_CLIENT ON FAWEB_CLIENT.CODE_CLIENT = LETTRE_VOIT.CODE_CLIENT
 LEFT  JOIN ORDRE ON ORDRE.CODE_DEST = LETTRE_VOIT.CODE_DEST AND ORDRE.CODE_CLIENT = LETTRE_VOIT.CODE_CLIENT
   AND ORDRE.DATE_CLOTUR = LETTRE_VOIT.DATE_CLOTURE
WHERE  LETTRE_VOIT.NO_ORDRE IN ('5530','5533')

as you can see on image i got double value of 5530 and 5533.

my table FAWEB_CLIENT with ID Code_Client
table LETTRE_VOIT with ID NOID and NO_ORDRE
table ORDRE with ID NO_ORDRE and NO_CLIENT

i can not use DISTINCT:
Distinct
error message: The text data type can not be selected as DISTINCT because it is not comparable

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T01:28:44+00:00Added an answer on June 16, 2026 at 1:28 am

    I suspect the problem is that your joins are not correct. My suspicion is that you are missing a join condition on Letter_Voit.No_Ordre:

    SELECT *
    FROM LETTRE_VOIT 
     LEFT JOIN FAWEB_CLIENT ON FAWEB_CLIENT.CODE_CLIENT = LETTRE_VOIT.CODE_CLIENT
     LEFT  JOIN ORDRE ON ORDRE.CODE_DEST = LETTRE_VOIT.CODE_DEST AND ORDRE.CODE_CLIENT = LETTRE_VOIT.CODE_CLIENT
       AND ORDRE.DATE_CLOTUR = LETTRE_VOIT.DATE_CLOTURE and
       LETTRE_VOIT.No_ORDRE = Order.No_ORDRE
    WHERE  LETTRE_VOIT.NO_ORDRE IN ('5530','5533')
    

    You may be able to remove some of the other join conditions, which may become redundant.

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