I made a chrome extension to search the website dev.bukkit.org, and it works great with this code:
<script>
function onLoad() {
document.getElementById("mytextfield").focus();
}
function onKeyPress(e) {
if (e.keyCode == 13) {
openResults();
}
}
function openHomePage() {
window.open("http://dev.bukkit.org/");
}
function openResults() {
window.open("http://dev.bukkit.org/search/?search=" + encodeURIComponent(document.getElementById("mytextfield").value));
}
</script>
</head>
<body onload="onLoad();">
<img src="png-3.png" onclick="openHomePage();" style="border-width: 0px; cursor: pointer" /><br>
<div name="myFormDiv" style="center: 6px;">
<br>
<center><input type="search" id="mytextfield" name="mytextfield" placeholder="Search..." onkeypress="onKeyPress(event);" /></center>
</div>
I now would like to make an option to search forum.bukkit.org. Unfortunately, it requires a token to search the forum. A friend gave me a php snippet that lets you search the forum, but I am having trouble integrating it into the original code to search dev.bukkit.org. Help would be appreciated, I am lost!
PHP Forum Search code:
<?php
$q=$_GET['q'];
echo do_post_request("http://forums.bukkit.org/search/search",'keywords='.$q.'&_xfToken=10000%2C1333276150%2C1b8a644c97b33e9cfda0e15170ca5185cf15bc3a');
function do_post_request($url, $data, $optional_headers = null)
{
$params = array('http' => array(
'method' => 'POST',
'content' => $data
));
if ($optional_headers !== null) {
$params['http']['header'] = $optional_headers;
}
$ctx = stream_context_create($params);
$fp = @fopen($url, 'rb', false, $ctx);
if (!$fp) {
throw new Exception("Problem with $url, $php_errormsg");
}
$response = @stream_get_contents($fp);
if ($response === false) {
throw new Exception("Problem reading data from $url, $php_errormsg");
}
return $response;
}
?>
Thank you:)
Based on Adding custom HTTP headers using JavaScript, you should use
XmlHttpRequest. My personal suggestion would be to use ajax to call php script and retrieve data. You can implement it easily with jQuery’s .post().