Question

I made some code, for understanding the concept/basic of pointer:

int a=1;
int *b=&a;
int **c = &b;
int ***d = &c;

cout << &*(&*d) << endl;

Why does &*(&*d) return address of "c" instead of address of "b"?

I’ve also tried code like &*(&*(&*(&*(&*d)))), but it keep return address of "c"

Answer 1

Because the &* cancels each other out. * dereference d which gives the value of c. And then & gives the address of c, or the value of d.